How do you solve $4sinx=-2sinx-5$ ?

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Answer 1 · 2018-04-18T16:51:46

$x = npi -(-1)^nsin^(-1)(5/6)$

$4sinx=-2sinx-5$

$rArr 6sinx=-5$
$rArrsinx=-5/6$

Now writing down the general solution for $sinx=sintheta$ :-

$rArr x = npi +(-1)^nsin^(-1)(-5/6)$

$:. x = npi -(-1)^nsin^(-1)(5/6)$ .........{ $sin^(-1)(-theta)=-sin^(-1)theta$ }

Here $n$ is any Integer value.

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