How do you solve $4sin(x+pi)=2cos(x+pi/2)+2$ ?

Question

2395 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-14T09:27:02

$x=2npi-pi/2$

We can solve the equation $4sin(x+pi)=2cos(x+pi/2)+2$ ,

by using the identities $sin(x+pi)=-sinx$ and $cos(x+pi/2)=-sinx$

Hence $4sin(x+pi)=2cos(x+pi/2)+2$ can be written as

$-4sinx=-2sinx+2$ or

$-4sinx+2sinx=2$ or

$-2sinx=2$ or

$sinx=-1=son(-pi/2)$

Hence $x=2npi-pi/2$

How do you solve 4sin(x+pi)=2cos(x+pi/2)+24sin(x+pi)=2cos(x+pi/2)+2?