How do you solve 4sin x cos x - 2sqrt2sin x + 2cos x - sqrt2 = 0 from 0 to 2pi?

1 Answer
Sasha P.
Sep 14, 2015

x=pi/4 or x=(7pi)/4 or x=(7pi)/6 or x=(11pi)/6

Explanation:

4sinxcosx-2sqrt2sinx+2cosx-sqrt2=0
2sinx(2cosx-sqrt2)+2cosx-sqrt2=0
(2cosx-sqrt2)(2sinx+1)=0
2cosx-sqrt2=0 or 2sinx+1=0
cosx=sqrt2/2 or sinx=-1/2
x=pi/4 or x=(7pi)/4 or x=(7pi)/6 or x=(11pi)/6

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