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How do you solve $4sin^2x-4sinx+1=0$ ?

1 Answer

Sep 20, 2016

$x = pi/6+2kpi, pi=0,pm1,pm2,cdots$

Explanation:

Solving for $sinx$

$4sin^2x-4sinx+1=0$

$sinx = (4pmsqrt(4^2-4^2))/8=1/2$

then

$x = arcsin(1/2)+2kpi, pi=0,pm1,pm2,cdots$

$x = pi/6+2kpi, pi=0,pm1,pm2,cdots$

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