How do you solve 4p^2=-7p-3 using the quadratic formula?

1 Answer
ThisIsSomeone
Apr 11, 2018

See Explanation

Explanation:

To solve, you must first move all the terms to one side, so: 4p^2+7p+3=0. Then, the quadratic formula is x=\frac {-b\pm \sqrt {b^{2}-4ac}}(2a). Plug in 4 for a, 7 for b and 3 for c. You get x=\frac {-7\pm \sqrt {7^{2}-4*4*3}}(2*4)=\frac {-7\pm 1}(8) so, x=(-7+1)/(8)=-6/8=-3/4 and x=(-7-1)/(8)=(-8)/8=-1. x=-1 and -3/4

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