How do you solve #4(y-3)=48#?

2 Answers
mason m
Jun 15, 2017

#y=15#

Explanation:

First, divide both sides of the equation by #4#. You could also start by distributing the #4# into the parentheses but that will only make this problem take more time.

#y-3=48/4=12#

Add #3# to both sides.

#y=15#

Jim G.
Jun 15, 2017

#y=15#

Explanation:

#"divide both sides of the equation by 4"#

#4/4(y-3)=48/4#

#rArry-3=12#

#"add 3 to both sides"#

#ycancel(-3)cancel(+3)=12+3#

#rArry=15#

#color(blue)"As a check"#

#4(15-3)=4xx12=48=" right side"#

#rArry=15" is the solution"#

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