How do you solve $4/(x-8)>0$ ?

Question

1962 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-07T06:40:19

The answer is $x in ] 8,+oo[$

We solve this equation with a sign chart

Let $f(x)=4/(x-8)$

$color(white)(aaaa)$ $x$ $color(white)(aaaaaa)$ $-oo$ $color(white)(aaaaaa)$ $8$ $color(white)(aaaaaa)$ $+oo$

$color(white)(aaaa)$ $x-8$ $color(white)(aaaaaaa)$ $-$ $color(white)(aaaaaa)$ $+$

$color(white)(aaaa)$ $f(x)$ $color(white)(aaaaaaaaa)$ $-$ $color(white)(aaaaaa)$ $+$

Therefore,

$f(x)>0$ , when $x in ] 8,+oo[$

How do you solve 4/(x-8)>04/(x-8)>0?