How do you solve $(4-x)^{2}=36$ ?

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How do you solve $(4-x)^{2}=36$ ?

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Answer 1 · 2016-10-17T01:20:31

$x= -2$

Explanation:

$(4-x)^2 = 36$
Take the square root of each side.
$sqrt((4-x)^2) = sqrt36$
Simplifies it to:
$4-x = 6$
subtract 4 from each side:
$4-x-4 = 2-4$
simplifies it to:
$-x = 2$
Divide each side by -1:
$1x/-1 = 2/-1$
$x = -2$

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How do you solve $(4-x)^{2}=36$ ?

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