How do you solve 4x22x3=[xx3][1x+1]?

1 Answer
Oct 23, 2015

x=4

Explanation:

Start by simplifying the right side:
XXX(xx3)(1x+1)=xx22x3

So the given equation is equivalent to
XXX4x22x3=xx22x3

XXXx=4

This, of course, assumes x3 and x1; otherwise the original equation is meaningless.