How do you solve $4/(x+2)>2$ ?

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Answer 1 · 2016-09-23T21:06:31

$0>x$

We can rearrange this equation by treated the $>$ sign with
the $=$ sign

First we times both sides by $x+2$

$4/(x+2) > 2 to$

$4>2(x+2)$

When the bracket is multiplied out we get the equation;

$4>2x + 4$

Then we take $4$ from both sides

$0>2x$

Finally we divide both sides by $2$

$0>x$

How do you solve 4/(x+2)>24/(x+2)>2?