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How do you solve $4^(2-5x)=1/64$ ?

1 Answer

Konstantinos Michailidis

May 29, 2016

Notice $1/64=4^-3$ hence

$4^(2-5x)=4^-3=>log(4^(2-5x))=log4^-3=>(2-5x)=-3=>5=5x=>x=1$

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