How do you solve $4 = \frac{2}{3} x + 9 - \frac{1}{3} x$ $4=2/3x+9-1/3x$ ?

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Answer 1 · 2016-02-14T11:12:56

$x = - 15$ $x=-15$

$4 = \frac{2}{3} x + 9 - \frac{1}{3} x$ $4=2/3 x+9-1/3 x$

$\to 4 = \frac{2 x}{3} - \frac{x}{3} + 9$ $rarr4=(2x)/3-x/3+9$

$\to 4 = \frac{x}{3} + 9$ $rarr4=x/3+9$

$\to \frac{x}{3} + 9 = 4$ $rarrx/3+9=4$

$\to \frac{x}{3} = 4 - 9$ $rarrx/3=4-9$

$\to \frac{x}{3} = - 5$ $rarrx/3=-5$

$\Rightarrow x = - 5 \cdot 3 = - 15$ $rArrx=-5*3=-15$

How do you solve 4=23x+9−13x4=2/3x+9-1/3x?