How do you solve #3y-8=-6#?

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Answer 1 · 2017-02-01T03:21:56

See the entire solution process below:

First, add #color(red)(8)# to each side of the equation to isolate the #y# term while keeping the equation balanced:

#3y - 8 + color(red)(8) = -6 + color(red)(8)#

#3y - 0 = 2#

#3y = 2#

Now, divide each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#(3y)/color(red)(3) = 2/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = 2/3#

#y = 2/3#