How do you solve 3x(x+2)=2 using the quadratic formula?

1 Answer
Meave60
Jul 3, 2015

Convert the given equation to the form of a quadratic equation, ax^2+bx+c=0. Identify a, b, and c. Substitute the values into the quadratic formula x=(-b+-sqrt(b^2-4ac))/(2a), and solve for x. There will be two solutions for x.

Explanation:

The equation needs to be in the form ax^2+bx+c=0.

3x(x+2)=2

3x^2+6x=2

3x^2+6x-2=0

Quadratic Formula

x=(-b+-sqrt(b^2-4ac))/(2a)

a=3;b=6;c=-2

x=(-6+-sqrt(6^2-4*3*-2))/(2*3)

x=(-6+-sqrt(36+24))/(6)

x=(-6+-sqrt(60))/6

sqrt(60)=sqrt(4xx15)=2sqrt 15

x=(-6+-2sqrt15)/6

x=-1+(2sqrt 15)/3

x=-1-(2sqrt15)/3

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