How do you solve #3x + 6z = 0#, #-2x + y = 5#, #y + 2z = 3#?
1 Answer
Dec 31, 2016
Explanation:
Given
[1]
[2]
[3]
Statement [2]
[4]
Substituting from [4] into [3]
[5]
Simplifying
[6]
or
[7]
or
[8]
Substituting from [8] into [1]
[9]
Simplifying
[10]
or
[11]
Substituting from [11] into [8]
[12]
Substituting from [11] into [4]
[13]