How do you solve #3x² + 5x = 2#?

Question

How do you solve #3x² + 5x = 2#?

1 Answer

Impact of this question

2445 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-12T21:30:41

#x_1=-2#
#x_2=1/3#

Explanation:

#3x^2+5x=2#
#3x^2+5x-2=0#
#ax^2+bx+c=0#
#Delta=sqrt(b^2-4*a*c)#
#Delta=sqrt(5^2+4*3*2)#
#Delta=sqrt(25+24)" "Delta =sqrt49 " "Delta=±7#
#x_"1,2"=(-b±Delta)/(2*a)#
#x_1=(-b-Delta)/(2*a)=(-5-7)/(2*3)=(-12)/6#
#x_1=-2#
#x_2=(-b+Delta)/(2*a)=(-5+7)/(2*3)=2/6#
#x_2=1/3#

Science

Math

Humanities

... and beyond

How do you solve #3x² + 5x = 2#?

1 Answer

Explanation:

Related questions

Impact of this question