How do you solve ${(3 x - 4)}^{2} = 42$ $(3x-4)^2=42$ ?

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Answer 1 · 2017-06-09T03:02:01

See below.

We take the square root of both sides.

$3 x - 4 = \pm \sqrt{42}$ $3x-4=pmsqrt(42)$

$3 x = \pm \sqrt{42} + 4$ $3x=pmsqrt(42)+4$

$x = \frac{\pm \sqrt{42} + 4}{3}$ $x=(pmsqrt(42)+4)/3$

How do you solve (3x-4)^2=42(3x−4)2=42(3x-4)^2=42?