How do you solve $3x^2 - 8x + 2 = 0$ using the quadratic formula?

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How do you solve $3x^2 - 8x + 2 = 0$ using the quadratic formula?

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Answer 1 · 2016-05-03T19:53:44

Use the formula:

$x = (-b+-sqrt(b^2-4ac))/(2a)$

to find:

$x =(4+-sqrt(10))/3$

Explanation:

$3x^2-8x+2=0$ is of the form $ax^2+bx+c=0$ , with $a=3$ , $b=-8$ and $c=2$

This has roots given by the quadratic formula:

$x = (-b+-sqrt(b^2-4ac))/(2a)$

$=(8+-sqrt((-8)^2-(4*3*2)))/(2*3)$

$=(8+-sqrt(64-24))/6$

$=(8+-sqrt(40))/6$

$=(8+-sqrt(2^2*10))/6$

$=(8+-2sqrt(10))/6$

$=(4+-sqrt(10))/3$

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How do you solve $3x^2 - 8x + 2 = 0$ using the quadratic formula?

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