How do you solve 3x^2-8x=0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Aviv S. Mar 4, 2018 The answers are x=0, 8/3. Explanation: Factor out the x term, and then set each factor each to zero. 3x^2-8x=0 color(red)x*color(blue)(3x)-color(red)x*color(blue)8=0 color(red)x(color(blue)(3x-8))=0 color(white){color(black)((color(red)x=0, qquadqquad color(blue)(3x-8)=0), (color(red)x=0, qquadqquad color(blue)(3x)=8), (color(red)x=0, qquadqquad color(blue)x=8/3):} So the solutions are x=0, 8/3. Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 10074 views around the world You can reuse this answer Creative Commons License