How do you solve $3x^2+5x-2=0$ using the quadratic formula?

Question

28782 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-25T13:45:40

The solutions are: $color(blue)(x=1/3,x=-2$

The equation $3x^2+5x−2$ is of the form $color(blue)(ax^2+bx+c=0$

where:
$a=3, b=5, c=-2$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (5)^2-(4) * (3)*(-2)$

$= 25+24=49$

As $Delta>0$ there are two solutions,

The solutions are found using the formula:

$x=(-b+-sqrtDelta)/(2*a)$

As $Delta = 49$ , $x = (-(5)+-sqrt(49))/(2*3)= (-5+-7)/6$

$x=(-5-7)/6= color(blue)(-2$

$x=(-5+7)/6=color(blue)(1/3$

How do you solve 3x^2+5x-2=03x^2+5x-2=0 using the quadratic formula?