How do you solve 3x^2 - 4x - 8 = 0 using the quadratic formula?

1 Answer
Nghi N.
May 7, 2016

x = +- (2/3)(1 +- sqrt7)

Explanation:

Use the improved quadratic formula (Google, Yahoo Search)
D = d^2 = b^2 - 4ac = 16 + 96 = 112 = 16(7) --> d = +- 4sqrt7
There are 2 real roots:
x = -b/(2a) +- d/(2a) = 4/6 +- 4sqrt7/6 = +- (2/3)(1 +- sqrt7)

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