How do you solve #3x^2-4x=4#?

1 Answer
Don't Memorise
Jun 17, 2015

# color(green)( x=-2/3 and x=2#

Explanation:

Here, we can first factorise the expression and thereby find the solutions:

Factorising by splitting the middle term
#3x^2-4x -4 = 0#
# 3x^2-6x + 2x -4 =0#
# 3x(x-2) +2(x-2) = 0#
#color(green)( (3x+2)(x-2) =0#

Equating the factors with zero
# 3x +2 = 0 , x = -2/3#
# x-2 = 0 , x=2#

So the solutions are:
# color(green)( x=-2/3 and x=2#

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