How do you solve $3x^2 + 4 = -7x$ using the quadratic formula?

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Answer 1 · 2015-08-11T17:19:32

The solutions are
$color(blue)(x=-4/3 ,x=-1$

$3x^2+4=−7x$

$3x^2+ 7x+4=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=3, b=7, c=4$

The Discriminant is given by:
$Delta=b^2-4*a*c$
$= (7)^2-(4*3*4)$
$=49-48$
$= 1$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-7)+-sqrt(1))/(2*3) = (-7+-(1))/6$

$x=(-7-1)/6=-8/6 = -4/3$

$x=(-7+1)/6=-6/6 = -1$

The solutions are
$color(blue)(x=-4/3 ,x=-1$

How do you solve 3x^2 + 4 = -7x3x^2 + 4 = -7x using the quadratic formula?