How do you solve $3x^2 - 2x - 2 = 0$ using the quadratic formula?

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Answer 1 · 2018-03-28T13:09:40

Apply the formula:
$x_1=(-b+(b^2-4*a*c)^(1/2))/(2*a)$
$x_2=(-b-(b^2-4*a*c)^(1/2))/(2*a)$

$x_1=(-(-2)+((-2)^2-4*3*(-2))^(1/2))/(2*3)=(1+√7)/3$
$x_1=(-(-2)-((-2)^2-4*3*(-2))^(1/2))/(2*3)=(1-√7)/3$

How do you solve 3x^2 - 2x - 2 = 03x^2 - 2x - 2 = 0 using the quadratic formula?