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How do you solve #3x^2-15x=0 #?

↳Redirected from "What is the concentration of pure water at #298*K# given a #"density"# of #1.00*g*mL^-1#?"

1 Answer

Apr 2, 2016

The solutions are
#color(blue)(x=0#
#color(blue)(x=5#

Explanation:

#3x^2 - 15x = 0#

#3x# is common to both terms of the L.H.S:

#3x( x - 5) = 0#

Equating each of the factors to zero we obtain the solutions:
#3x= 0 , x = 0/3, color(blue)(x=0#

#x- 5= 0 , color(blue)(x=5#

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