How do you solve #3x^2=12#?

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Answer 1 · 2018-03-24T18:14:18

Divide to isolate x and find the square root.

# 3x^ = 12# divide both sides by 3

# 3x^2/3 = 12/3# this gives

# x^2 = 4# take the square root of both sides

# x = 2, -2#

Answer 2 · 2018-03-24T18:14:19

#x=+-2#

#3x^2=12#

#x^2=4 rarr# Divide each side by 3

#x=+-2 rarr# #(-2)^2=2^2=4#

There are two answers: -2 and 2