How do you solve $3x^2 – 10x + 5 = 0$ using the quadratic formula?

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Answer 1 · 2018-04-05T04:00:30

$(10 +- sqrt(40))/6$

$3x^2 - 10x + 5 = 0$

It’s in the form of

$ax^2 + bx + c = 0$

Comparing two equations

$a = 3$

$b = -10$

$c = 5$

$x = (-b +- sqrt(b^2 - 4ac))/(2a)$

$x = (-(-10) +- sqrt((-10)^2 - (4 × 3 × 5)))/(2 × 3)$

$x = (10 +- sqrt(100 - 60))/6$

$x = (10 +- sqrt(40))/6$

How do you solve 3x^2 – 10x + 5 = 03x^2 – 10x + 5 = 0 using the quadratic formula?