How do you solve $\frac{3 x - 1}{x} \leq - 1$ $(3x-1)/x<=-1$ ?

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Answer 1 · 2016-10-05T16:58:03

$4 x \leq 1$ $4x <= 1$

Multiply both sides by $x$ $x$

$3 x - 1 \leq - 1 \times x$ $3x-1 <= -1 xx x$

$3 x - 1 \leq - x$ $3x - 1 <= -x$

Add $1$ $1$ to both sides

$3 x \leq - x + 1$ $3x <= -x + 1$

Add $x$ $x$ to both sides

$4 x \leq 1$ $4x <= 1$

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