How do you solve 3sqrtk+1=63√k+1=6 and find any extraneous solutions?

1 Answer
Jim G.
Aug 26, 2016

25/9259

Explanation:

We require to isolate the square root term.

subtract 1 from both sides

rArr3sqrtk+cancel(1)-cancel(1)=6-1rArr3sqrtk=5

divide both sides by 3

rArr(cancel(3)^1 sqrtk)/cancel(3)^1=5/3rArrsqrtk=5/3

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Squaring both sides to obtain k

rArr(sqrtk)^2=(5/3)^2

rArrk=5^2/3^2=25/9

There are no extraneous solutions.

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