How do you solve $3 \sqrt{w + 1} = 6$ $3sqrt(w + 1 )= 6$ ?

Question

1419 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-31T06:21:22

$w = 3$ $w=3$

$3 \sqrt{w + 1} = 6$ $3sqrt(w+1)=6$

$\to \sqrt{w + 1} = \frac{6}{3}$ $rarrsqrt(w+1)=6/3$

$\to \sqrt{w + 1} = 2$ $rarrsqrt(w+1)=2$

Square both sides

$\to {(\sqrt{w + 1})}^{2} = 2^{2}$ $rarr(sqrt(w+1))^2=2^2$

$\to w + 1 = 4$ $rarrw+1=4$

$\to w = 4 - 1 = 3$ $rarrw=4-1=3$

How do you solve 3√w+1=63sqrt(w + 1 )= 6?