How do you solve #3sqrt(4y)=6#?

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Answer 1 · 2015-04-17T14:11:20

Take #3# to the right:
#sqrt(4y)=6/3#
#sqrt(4y)=2#
square both sides and solve for #y#

Answer 2 · 2015-04-17T15:51:54

Know that:

#sqrt(ab)=sqrt(a)sqrt(b)#

So:

#3sqrt(4y)=6#

#(3sqrt(4y))/3=6/3#

#sqrt(4y)=2#

#sqrt(4)sqrt(y)=2#

#(sqrt(4)sqrt(y))/sqrt(4)=2/(sqrt(4))#

#sqrt(y)=1#

#y=1^2#

#:.y=1#