How do you solve $3 (x + 8) = 12$ $3(x+8)=12$ ?

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How do you solve $3 (x + 8) = 12$ $3(x+8)=12$ ?

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Answer 1 · 2016-07-09T15:40:22

$x = - 4$ $x = -4$

Explanation:

There are 2 ways to approach this equation:

Using the distributive law,:

$3 (x + 8) = 12$ $3(x +8) = 12$
$3 x + 24 = 12$ $3x + 24 = 12$
$3 x = 12 - 24$ $3x = 12-24$
$3 x = - 12$ $3x = -12$
$x = \frac{- 12}{3}$ $x = (-12)/3$
$x = 4$ $x = 4$

Or by isolating the bracket by dividing both sides by 3 first:

$\frac{3 (x + 8)}{3} = \frac{12}{3}$ $(3(x +8))/3 = 12/3$

$x + 8 = 4$ $x + 8 = 4$
$x = 4 - 8$ $x = 4-8$
$x = - 4$ $x = -4$

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How do you solve $3 (x + 8) = 12$ $3(x+8)=12$ ?

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Explanation:

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