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How do you solve $3(x-4)^2=15$ ?

1 Answer

Jul 24, 2016

$x=4+sqrt5$
$x=4-sqrt5$

Explanation:

$3(x-4)^2=15$
or
$(x-4)^2=5$
or
$x-4=+-sqrt5$
or
$x=4+sqrt5$ ------Ans $1$
or
$x=4-sqrt5$ -------Ans $2$

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