How do you solve $3 {(x + 1)}^{2} = 24$ $3(x+1)^2=24$ ?

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How do you solve $3 {(x + 1)}^{2} = 24$ $3(x+1)^2=24$ ?

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Answer 1 · 2017-07-13T21:19:20

$x = - 1 \pm 2 \sqrt{2}$ $x=-1+-2sqrt2$

Explanation:

$3 {(x + 1)}^{2} = 24$ $3(x+1)^2=24$
${(x + 1)}^{2} = 8$ $(x+1)^2=8$ $\to$ $->$ divide both sides by $3$ $3$
$x + 1 = \sqrt{8}$ $x+1=sqrt8$ $\to$ $->$ take the square root of both sides
$x + 1 = \pm 2 \sqrt{2}$ $x+1=+-2sqrt2$ $\to$ $->$ simplify the left side
$x = - 1 \pm 2 \sqrt{2}$ $x=-1+-2sqrt2$ $\to$ $->$ subtract $1$ $1$ from both sides

$x = - 1 \pm 2 \sqrt{2}$ $x=-1+-2sqrt2$

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How do you solve $3 {(x + 1)}^{2} = 24$ $3(x+1)^2=24$ ?

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How do you solve 3(x+1)2=243(x+1)^2=24?

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How do you solve $3 {(x + 1)}^{2} = 24$ $3(x+1)^2=24$ ?