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How do you solve #3 log x=1.5#?

1 Answer

Dec 21, 2015

#x=sqrt(10)#

Explanation:

#3log(x) = log(x^3)#

#10^(log(x^3)) = x^3#

So if #3log(x) = 1.5#
then
#color(white)("XXX")x^3= 10^(1.5) = 10^(0.5)xx10^(0.5)xx10^(05)#

#color(white)("XXX")rarr x= 10^(0.5) = sqrt(10)#

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