How do you solve $(\frac{3}{7}) x + 2 = 4$ $(3/7)x+2=4$ ?

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Answer 1 · 2017-02-11T21:27:48

See the entire solution process below:

Step 1) Subtract $2$ $color(red)(2)$ from each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$(\frac{3}{7}) x + 2 - 2 = 4 - 2$ $(3/7)x + 2 - color(red)(2) = 4 - color(red)(2)$

$(\frac{3}{7}) x + 0 = 2$ $(3/7)x + 0 = 2$

$(\frac{3}{7}) x = 2$ $(3/7)x = 2$

Step 2) Multiply each side of the equation by $\frac{7}{3}$ $color(red)(7)/color(blue)(3)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{7}{3} \times (\frac{3}{7}) x = \frac{7}{3} \times 2$ $color(red)(7)/color(blue)(3) xx (3/7)x = color(red)(7)/color(blue)(3) xx 2$

$cancel(color(red)(7))/cancel(color(blue)(3)) xx (color(blue)(cancel(color(black)(3)))/color(red)(cancel(color(black)(7))))x = 14/color(blue)(3)$

$x = 14/3$

How do you solve (3/7)x+2=4(37)x+2=4(3/7)x+2=4?