How do you solve $3 = (6 x^{2}) e^{2 x^{3} - 3}$ $3 = (6x^2)e^(2x^3 - 3)$ ?

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Answer 1 · 2018-06-21T14:45:53

we get $x \approx 1.03746206802428772928$ $xapprox 1.03746206802428772928$

Writing
$2 x^{2} e^{2 x^{3} - 3} = 1$ $2x^2e^(2x^3-3)=1$
we get by a numerical method

$x \approx 1.03746206802428772928$ $x approx 1.03746206802428772928$

How do you solve 3=(6x2)e2x3−33 = (6x^2)e^(2x^3 - 3)?