How do you solve #3 * 5^(x-1) + 5^x = 0.32#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Cesareo R. May 15, 2016 #x = -1# Explanation: The equation can be written as #3/5 5^x + 5^x = (3/5+1)5^x =0.32# arriving at #5^x = 0.2 = 5^(-1)# then equating exponents #x = -1# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 1518 views around the world You can reuse this answer Creative Commons License