How do you solve 3^(-3p)=3^(3p)?

2 Answers

We have

3^(-3p)=3^(3p)

1/(3^(3p))=3^(3p)

1=3^(3p+3p)

1=3^(6p)

ln1=6*p*ln3 (take logarithms on both sides)

0=p*(6*ln3)

p=0

Hence p=0

We have

3^(-3p)=3^(3p)

1/(3^(3p))=3^(3p)

1=3^(3p+3p)

1=3^(6p)

ln1=6*p*ln3 (take logarithms on both sides)

0=p*(6*ln3)

p=0

Hence p=0