How do you solve # 3.2y-1.8=3#?

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Answer 1 · 2018-03-07T09:05:18

See a solution process below:

First, add #color(red)(1.8)# to each side of the equation to isolate the #y# term while keeping the equation balanced:

#3.2y - 1.8 + color(red)(1.8) = 3 + color(red)(1.8)#

#3.2y - 0 = 4.8#

#3.2y = 4.8#

Now, divide each side of the equation by #color(red)(3.2)# to solve for #y# while keeping the equation balanced:

#(3.2y)/color(red)(3.2) = 4.8/color(red)(3.2)#

#(color(red)(cancel(color(black)(3.2)))y)/cancel(color(red)(3.2)) = (1.6 xx 3)/color(red)(1.6 xx 2)#

#y = (color(red)(cancel(color(black)(1.6))) xx 3)/color(red)(color(black)(cancel(color(red)(1.6))) xx 2)#

#y = 3/color(red)(2)#

#y = 1.5#