How do you solve #3/2=11/(2m)-m-2/m#?

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Answer 1 · 2016-01-24T00:08:03

#x=-2.766 " or " + 1.266" "# to 3 decimal places

If you need more detail about the calc go to my profile page and put a not on it!

#3/2 = (11-2m^2-4)/(2m)#

#6m=22-4m^2-8#

#4m^2+6m-14=0#

#(am+?)(bm+?)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Attempt 1")#
#(4m-2)(m+7) -> 4m^2+28m-2m-14color(red)(" Fail!")#

#color(blue)("Attempt 2")#
#(m-2)(4m+7)->4m^2+7m-2m-14color(red)(" Fail!")#

#color(blue)("Attempt 3")#
#(2m-2)(2m+7)->4m^2 +14m-4m-14 color(red)(" Fail!")#

#color(blue)("Attempt 4")#

#x=(-6+-sqrt(6^2-4(4)(-14)))/(2(4))#

#x=(-6+-sqrt(36 +224))/8#

#x= (-6+-sqrt(260))/8#

#x=(-6+-2sqrt(65))/8#

(-6-

#x=-2.766 " or " + 1.266" "# to 3 decimal places

Tony B