How do you solve #3- 1+ 6+ ( - 6)^{2} + | 3\cdot 2|#?

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Answer 1 · 2016-09-23T10:16:00

#50#

We have: #3 - 1 + 6 + (- 6)^(2) + abs(3 cdot 2)#

#= 3 - 1 + 6 + 36 + abs(3 cdot 2)#

#= 3 - 1 + 6 + 36 + abs(6)#

#= 3 - 1 + 6 + 36 + 6#

#= 3 + 6 + 36 + 6 - 1#

#= 9 + 42 - 1#

#= 51 - 1#

#= 50#