How do you solve $2 y - (5 y + 1) = 1$ $2y-(5y+1)=1$ ?

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How do you solve $2 y - (5 y + 1) = 1$ $2y-(5y+1)=1$ ?

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Answer 1 · 2017-11-03T09:35:02

By arranging the equation.

Explanation:

Your equation

$2 y - 5 y - 1 = 1$ $2y - 5y - 1 = 1$

When you rewrite down after combining y and numbers:

$- 3 y = 1 + 1$ $-3y = 1+1$

$- 3 y = 2$ $-3 y = 2$

$y = - \frac{2}{3}$ $y= -2/3$

Answer 2 · 2017-11-03T09:35:36

the solution is $y = - \frac{2}{3}$ $y=-2/3$

Explanation:

the given equation is $2 y - (5 y + 1) = 1$ $2y-(5y+1)=1$ $\Rightarrow 2 y - 5 y - 1 = 1$ $rArr2y-5y-1=1$
$\Rightarrow - 3 y = 2$ $rArr-3y=2$ $\Rightarrow y = - \frac{2}{3}$ $rArry=-2/3$

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How do you solve $2 y - (5 y + 1) = 1$ $2y-(5y+1)=1$ ?

2 Answers

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