How do you solve (2x)/(x+5)<=0?

1 Answer
Dec 16, 2016

-5 < x <= 0

Explanation:

color(red)("There is a trap in this question in that there are excluded")color(red)("values for "x)

color(blue)("Step 1")
Solve disregarding the excluded values.

Multiply both sides by (x+5)

2x<=0xx(x+5)

2x<=0

color(blue)("Condition 1: "x<=0)

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color(blue)("Step 2")
An equation or expression becomes 'undefined' if you have division by 0.

=>(x+5) != 0

color(blue)("Condition 2: "x!=-5)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(blue)("Step 3")

Can we have x< -5color(white)(.)?

Suppose x=-6 then we have:

(2(-6))/(-6+5) = (-12)/-1=+12

This is not an excluded value but does not satisfy (2x)/(x+5)<=0
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color(blue)("Putting it all together using proper notation")

-5 < x <= 0