How do you solve #2x+6/3 = x - 1/5#?

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Answer 1 · 2016-03-08T12:55:30

#-11/5#

#2x+6/3=x-1/5#

Subtract #x# both sides

#rarrcancel(2x)+6/3-cancelx=cancelx-1/5-cancelx#

#rarrx+6/3=-1/5#

Subtract #6/3# both sides

#rarrx+cancel(6/3)-cancel(6/3)=-1/5-6/3#

#rarrx=-1/5-6/3#

#rArrx=-1/5-2=-11/5#