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How do you solve #2x²+3x=5 # using the quadratic formula?

1 Answer

Nghi N. · MathFact-orials.blogspot.com

Feb 11, 2017

#- 5/2, 1#

Explanation:

Bring the equation to standard form:

#y = 2x^2 + 3x - 5 = 0#.

Use the improved quadratic formula (Socratic Search)(https://socratic.org/questions/what-is-the-improved-quadratic-formula-in-solving-quadratic-equations?source=search):

#D = d^2 = b^2 - 4ac = 9 + 40 = 49# --> #d = +- 7#

There are 2 real roots:

#x = - b/(2a) +- d/(2a) = - 3/4 +- 7 /4#

#x1 =( - 3 - 7)/4 = - 10/4 = -5/2#

#x2 = (- 3 + 7)/4 = 4/4 = 1#

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