How do you solve (2x+3)(x+4)=1 for x using the square root property?

1 Answer
Manikandan S.
Jul 3, 2017

(2x+3)(x+4)=1
2x^2+7x+12 =1
2(x^2+7/2x+49/16)+12-49/8=1
2(x+7/4)^2+47/8=1
2(x+7/4)^2=-39/8
(x+7/4) = \pm sqrt(39/16)i
x = (-7+- sqrt(39)i)/4

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