How do you solve $2x^2-x= -5$ using the quadratic formula?

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Answer 1 · 2016-04-26T14:31:02

The solutions for the equation are:

$color(green)( x = (1+sqrt(-39))/4, color(green)( x = (1-sqrt(-39))/4$

$2x^2 - x = -5$

$2x^2 - x + 5 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=2, b=-1, c=5$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (-1)^2-(4* 2 * 5)$

$= 1 - 40 = - 39$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-1)+-sqrt(-39))/(2*2) = (1+-sqrt(-39))/4$

The solutions are:

How do you solve 2x^2-x= -52x^2-x= -5 using the quadratic formula?