How do you solve $2 x^{2} - x = 0$ $2x^2-x=0$ ?

1 Answer

May 21, 2015

Collect $x$ $x$ :
$x (2 x - 1) = 0$ $x(2x-1)=0$
The expression on the left is equal to zero only if:
1) $x = 0$ $x=0$
or
2) $2 x - 1 = 0$ $2x-1=0$ i.e. $x = \frac{1}{2}$ $x=1/2$

which are your two solutions.

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How do you solve $2 x^{2} - x = 0$ $2x^2-x=0$ ?

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