How do you solve $2x^2 + 9x + 4 = 0$ using the quadratic formula?

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Answer 1 · 2016-02-27T07:20:58

$x=( -1)/(2) or x=-4$

Given equation is $2x^2+9x+4=0$
Comparing with $ax^2+bx+c=0$

We get, $a= 2; b=9, c= 4$

$x=( -b+-sqrt(b^2-4ac))/(2a)$

$x=( -9+-sqrt(9^2-4xx2xx4))/(2xx2)$

$x=( -9+-sqrt(81-32))/(4)$

$x=( -9+-sqrt(49))/(4)$

$x=( -9+-7)/(4)$

$x=( -9+7)/(4) or x=( -9-7)/(4)$

$x=( -2)/(4) or x=( -16)/(4)$

$x=( -1)/(2) or x=-4$

How do you solve 2x^2 + 9x + 4 = 02x^2 + 9x + 4 = 0 using the quadratic formula?